What is the extreme f(x)=0.00397t^2-0.593t+33.718 ?

The extreme f(x)=0.00397t^2-0.593t+33.718 is Minimum((0.593)/(0.00794),11.57385…)

Popular >

extreme f(x)=0.00397t^2-0.593t+33.718

extreme points

f (x) = 0.00397 t^{2} - 0.593 t + 33.718

Minimum (\frac{0.593}{0.00794}, 11.57385 \dots)

Solution steps

f^{'} (t) = 0.00794 t - 0.593

Find intervals:

Decreasing

: - \infty < t < \frac{0.593}{0.00794},

Increasing

: \frac{0.593}{0.00794} < t < \infty

Plug

t = \frac{0.593}{0.00794}

into

0.00397 t^{2} - 0.593 t + 33.718 : 11.57385 \dots

Minimum (\frac{0.593}{0.00794}, 11.57385 \dots)

f (x) = f (x) = e x - x, - 4 \leq x \leq 2

f (x) = 4 x^{2} - 48 x + 190

f (x, y) = e^{9 x^{2} + 6 y^{2} + 1}

f (x) = (\frac{3 - cos ( θ )}{sin ( θ )})

f (x y) = - x^{3} - y^{2} + 3 x - 2 y

What is the extreme f(x)=0.00397t^2-0.593t+33.718 ?
The extreme f(x)=0.00397t^2-0.593t+33.718 is Minimum((0.593)/(0.00794),11.57385…)