en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-2x^2-4x+3

Solution

extreme points

f (x) = - 2 x^{2} - 4 x + 3

Solution

Maximum (- 1, 5)

Solution steps

f^{'} (x) = - 4 x - 4

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < \infty

Plug

x = - 1

into

- 2 x^{2} - 4 x + 3 : 5

Maximum (- 1, 5)

Popular Examples

extreme f(x)=x^2log_{9}(x)extreme points

f (x) = x^{2} lo g_{9} (x)

extreme f(x)=2000+530(ln(x))extreme points

f (x) = 2000 + 530 (ln (x))

extreme f(x)=(3x+4)/(6x+1)extreme points

f (x) = \frac{3 x + 4}{6 x + 1}

extreme f(x)=3x^4-96x^2+1 extreme points

f (x) = 3 x^{4} - 96 x^{2} + 1

extreme f(x)=0.003x^2+4.2x-50 extreme points

f (x) = 0.003 x^{2} + 4.2 x - 50

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2-4x+3 ?
The extreme f(x)=-2x^2-4x+3 is Maximum(-1,5)