What is the extreme f(x)=0.003x^2+4.2x-50 ?

The extreme f(x)=0.003x^2+4.2x-50 is Minimum(-700,-1520)

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extreme f(x)=0.003x^2+4.2x-50

extreme points

f (x) = 0.003 x^{2} + 4.2 x - 50

Minimum (- 700, - 1520)

Solution steps

f^{'} (x) = 0.006 x + 4.2

Find intervals:

Decreasing

: - \infty < x < - 700,

Increasing

: - 700 < x < \infty

Plug

x = - 700

into

0.003 x^{2} + 4.2 x - 50 : - 1520

Minimum (- 700, - 1520)

f (x) = - 3 x^{2} + 1

f (x) = - 3 x^{2} + 3

f (x) = 2 x^{3} + x^{2} - 20 x

f (x) = 2 x^{2} - 4 x [0.3]

f (x y) = 4 x + 8 y

What is the extreme f(x)=0.003x^2+4.2x-50 ?
The extreme f(x)=0.003x^2+4.2x-50 is Minimum(-700,-1520)