What is the extreme f(x)=2x^3+x^2-20x ?

The extreme f(x)=2x^3+x^2-20x is Maximum(-2,28),Minimum(5/3 ,-575/27)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3+x^2-20x

extreme points

f (x) = 2 x^{3} + x^{2} - 20 x

Maximum (- 2, 28), Minimum (\frac{5}{3}, - \frac{575}{27})

Solution steps

f^{'} (x) = 6 x^{2} + 2 x - 20

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < \frac{5}{3},

Increasing

: \frac{5}{3} < x < \infty

Plug

x = - 2

into

2 x^{3} + x^{2} - 20 x : 28

Maximum (- 2, 28)

Plug

x = \frac{5}{3}

into

2 x^{3} + x^{2} - 20 x : - \frac{575}{27}

Minimum (\frac{5}{3}, - \frac{575}{27})

Maximum (- 2, 28), Minimum (\frac{5}{3}, - \frac{575}{27})

f (x) = 2 x^{2} - 4 x [0.3]

f (x y) = 4 x + 8 y

5 sin (3 x) - 5

f (x, y) = 3 x^{2} y + 4 x y - 2

\frac{1}{2} (5 x - 3)

What is the extreme f(x)=2x^3+x^2-20x ?
The extreme f(x)=2x^3+x^2-20x is Maximum(-2,28),Minimum(5/3 ,-575/27)