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Popular >

extreme f(x)=2x^2-4x[0.3]

Solution

extreme points

f (x) = 2 x^{2} - 4 x [0.3]

Solution

Minimum (0.3, - 0.18)

Solution steps

f^{'} (x) = 4 x - 1.2

Find intervals:

Decreasing

: - \infty < x < 0.3,

Increasing

: 0.3 < x < \infty

Plug

x = 0.3

into

2 x^{2} - 4 x [0.3] : - 0.18

Minimum (0.3, - 0.18)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-4x[0.3] ?
The extreme f(x)=2x^2-4x[0.3] is Minimum(0.3,-0.18)