What is the extreme f(x)=2x^2-7,-7<= x<= 7 ?

The extreme f(x)=2x^2-7,-7<= x<= 7 is Maximum(-7,91),Minimum(0,-7),Maximum(7,91)

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extreme f(x)=2x^2-7,-7<= x<= 7

extreme points

f (x) = 2 x^{2} - 7, - 7 \leq x \leq 7

Maximum (- 7, 91), Minimum (0, - 7), Maximum (7, 91)

Solution steps

Find the critical points:

x = - 7, x = 0, x = 7

Domain of

2 x^{2} - 7, - 7 \leq x \leq 7 : - 7 \leq x \leq 7

Find intervals:

Decreasing

: - 7 < x < 0,

Increasing

: 0 < x < 7

Plug the extreme point

x = - 7

into

2 x^{2} - 7 \Rightarrow y = 91

Maximum (- 7, 91)

Plug the extreme point

x = 0

into

2 x^{2} - 7 \Rightarrow y = - 7

Minimum (0, - 7)

Plug the extreme point

x = 7

into

2 x^{2} - 7 \Rightarrow y = 91

Maximum (7, 91)

Maximum (- 7, 91), Minimum (0, - 7), Maximum (7, 91)

x^{2} - 18 x + 86

2 x^{2} - 4 x + 6

f (x) = 3 (x - e^{x})

f (x) = x^{3} + 2 x^{2} - 4 x + 7

f (x, y) = - 4 x y + 2 x^{2} - 10 y^{2} - 4 y^{3} - 1

What is the extreme f(x)=2x^2-7,-7<= x<= 7 ?
The extreme f(x)=2x^2-7,-7<= x<= 7 is Maximum(-7,91),Minimum(0,-7),Maximum(7,91)