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Popular >

extreme y=(x-6)ln(x-6)

Solution

extreme points

y = (x - 6) ln (x - 6)

Solution

Minimum (\frac{1}{e} + 6, - \frac{1}{e})

Solution steps

f^{'} (x) = ln (x - 6) + 1

Find intervals:

Decreasing

: 6 < x < \frac{1}{e} + 6,

Increasing

: \frac{1}{e} + 6 < x < \infty

Plug

x = \frac{1}{e} + 6

into

(x - 6) ln (x - 6) : - \frac{1}{e}

Minimum (\frac{1}{e} + 6, - \frac{1}{e})

Popular Examples

extreme f(x,y)=(2y^2+x^2)e^{-(x^2+y^2-3)}extreme points

f (x, y) = (2 y^{2} + x^{2}) e^{- (x^{2} + y^{2} - 3)}

extreme p(x)=12x^4-62x^3+ax^2-98x+30 extreme points

p (x) = 12 x^{4} - 62 x^{3} + a x^{2} - 98 x + 30

extreme y=3z^2-3x^2 extreme points

y = 3 z^{2} - 3 x^{2}

extreme 4-y^3-x^2-3xy extreme points

4 - y^{3} - x^{2} - 3 x y

extreme (10x^3-2)/(2x^3+5x^2+9x)extreme points

\frac{10 x ^{3} - 2}{2 x ^{3} + 5 x ^{2} + 9 x}

Frequently Asked Questions (FAQ)

What is the extreme y=(x-6)ln(x-6) ?
The extreme y=(x-6)ln(x-6) is Minimum(1/e+6,-1/e)