What is the domain of f(x)=((x^2-9))/((x-3)) ?

The domain of f(x)=((x^2-9))/((x-3)) is x 3

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Find Where Undefined/Discontinuous f(x)=(x^2-9)/(x-3)

domain

f (x) = \frac{( x ^{2} - 9 )}{( x - 3 )}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

y = 7 - 4 x + x^{2}

f (x) = x^{2} + 2 x, x = 1

g (f) = 32 f

\frac{x , 1 , ( x - 1 )}{( x ^{2} - 4 )}

g (f) = 21 f

What is the domain of f(x)=((x^2-9))/((x-3)) ?
The domain of f(x)=((x^2-9))/((x-3)) is x<3\lor x>3