What is the domain of sqrt(1+x^2) ?

The domain of sqrt(1+x^2) is -infinity <x<infinity

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domain of sqrt(1+x^2)

domain

1 + x^{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

- x^{3} + 9 x^{2} - 27 x + 8

\frac{1}{t}

\frac{1 + sin ( x )}{x + cos ( x )}

f (x) = (x + 3)^{2} - 8

f (x) = x^{2} + 12 x + 40

What is the domain of sqrt(1+x^2) ?
The domain of sqrt(1+x^2) is -infinity <x<infinity