What is the range of 1/(sqrt(x-1)) ?

The range of 1/(sqrt(x-1)) is f(x)>0

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range of 1/(sqrt(x-1))

range

\frac{1}{x - 1}

f (x) > 0

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{1}{x - 1} : x > 1

Extreme Points of

\frac{1}{x - 1} :

None

Find the range for the interval

1 < x < \infty : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

f (x) = \frac{2 x + 1}{x ^{2} - x - 6}

f (x) = (x^{2} - 1)^{3}

1

x^{5} - 5 x

\frac{( x + 3 ) ( x - 3 )}{x ^{2} + 9}