What is the domain of ((x+3)(x-3))/(x^2+9) ?

The domain of ((x+3)(x-3))/(x^2+9) is -infinity <x<infinity

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domain of ((x+3)(x-3))/(x^2+9)

domain

\frac{( x + 3 ) ( x - 3 )}{x ^{2} + 9}

- \infty < x < \infty

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

cos (\frac{x}{4} + \frac{π}{4}) - 2

f (x) = \frac{2 x ^{2} - x - 7}{x ^{2} + 4}

f (x) = 1 - (x - 4)^{2}

\frac{4}{x} + 6

What is the domain of ((x+3)(x-3))/(x^2+9) ?
The domain of ((x+3)(x-3))/(x^2+9) is -infinity <x<infinity