What is the inverse of f(x)=(x+4)^2-4 ?

The inverse of f(x)=(x+4)^2-4 is sqrt(x+4)-4,-sqrt(x+4)-4

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inverse of f(x)=(x+4)^2-4

inverse

f (x) = (x + 4)^{2} - 4

x + 4 - 4, - x + 4 - 4

Solution steps

y = (x + 4)^{2} - 4

Replace

x

with

y

x = (y + 4)^{2} - 4

Solve for

y, x = (y + 4)^{2} - 4

x + 4 - 4, - x + 4 - 4

f (x) = - 4 x - 7

4 x - 3 y = 15

\frac{4}{x ^{2} + x - 2}

7 y = 5 x^{2} - 4

y = \frac{5}{x ^{2} - 1}

What is the inverse of f(x)=(x+4)^2-4 ?
The inverse of f(x)=(x+4)^2-4 is sqrt(x+4)-4,-sqrt(x+4)-4