What is the asymptotes of h(t)=(t^2-4t)/(t^4-256) ?

The asymptotes of h(t)=(t^2-4t)/(t^4-256) is Vertical: t=-4,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of h(t)=(t^2-4t)/(t^4-256)

asymptotes

h (t) = \frac{t ^{2} - 4 t}{t ^{4} - 256}

Vertical : t = - 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{t ^{2} - 4 t}{t ^{4} - 256} : t = - 4

Horizontal Asymptotes of

\frac{t ^{2} - 4 t}{t ^{4} - 256} : y = 0

Slant Asymptotes of

\frac{t ^{2} - 4 t}{t ^{4} - 256} :

None

Vertical : t = - 4, Horizontal : y = 0

3 x + 12 y = 24

f (x) = 3 x - 4

f (x) = \frac{x}{x ^{2} + 16 x + 60}

f (x) = \frac{1}{x - 1}

\frac{6 x - 1}{2 x + 5}

What is the asymptotes of h(t)=(t^2-4t)/(t^4-256) ?
The asymptotes of h(t)=(t^2-4t)/(t^4-256) is Vertical: t=-4,Horizontal: y=0