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Popular >

midpoint (2,-3),(-2,5)

Solution

midpoint

(2, - 3), (- 2, 5)

Solution

(0, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 3), (x_{2}, y_{2}) = (- 2, 5)

= (\frac{- 2 + 2}{2}, \frac{5 - 3}{2})

Refine

= (0, 1)

Popular Examples

critical 8-3x-2x^2 critical points

8 - 3 x - 2 x^{2}

domain of f(x)=e^{-4t}domain

f (x) = e^{- 4 t}

inverse of y=x^2+4 inverse

y = x^{2} + 4

symmetry y=(x+3)^2 symmetry

y = (x + 3)^{2}

line (14,-1.5),(16,0)line

(14, - 1.5), (16, 0)

Frequently Asked Questions (FAQ)

What is the midpoint (2,-3),(-2,5) ?
The midpoint (2,-3),(-2,5) is (0,1)