What is the inverse of f(x)=9+2\sqrt[3]{x} ?

The inverse of f(x)=9+2\sqrt[3]{x} is (x^3)/8-(27x^2)/8+(243x)/8-729/8

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inverse of f(x)=9+2\sqrt[3]{x}

inverse

\frac{x ^{3}}{8} - \frac{27 x ^{2}}{8} + \frac{243 x}{8} - \frac{729}{8}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{8} - \frac{27 x ^{2}}{8} + \frac{243 x}{8} - \frac{729}{8}

\frac{1}{x + 1}

(x^{2} + 6) (36 - x^{2})

x^{2} + 2 x + 2

f (x) = - 3 x + 3 y = - 9

f (x) = cos (2 x + π)

What is the inverse of f(x)=9+2\sqrt[3]{x} ?
The inverse of f(x)=9+2\sqrt[3]{x} is (x^3)/8-(27x^2)/8+(243x)/8-729/8