What is the inverse of f(x)=2(x+2)^2-3 ?

The inverse of f(x)=2(x+2)^2-3 is sqrt((x+3)/2)-2,-sqrt((x+3)/2)-2

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inverse of f(x)=2(x+2)^2-3

inverse

f (x) = 2 (x + 2)^{2} - 3

\frac{x + 3}{2} - 2, - \frac{x + 3}{2} - 2

Solution steps

y = 2 (x + 2)^{2} - 3

Replace

x

with

y

x = 2 (y + 2)^{2} - 3

Solve for

y, x = 2 (y + 2)^{2} - 3

\frac{x + 3}{2} - 2, - \frac{x + 3}{2} - 2

f (x) = \frac{3 x - 4}{2 x + 1}

f (x) = - x^{3} + 3 x^{2} - 2

f (x) = x^{3} - 9 x^{2} + 15 x - 6

(x^{2} - 7)^{3}

f (x) = \frac{5}{4 x - 8}

What is the inverse of f(x)=2(x+2)^2-3 ?
The inverse of f(x)=2(x+2)^2-3 is sqrt((x+3)/2)-2,-sqrt((x+3)/2)-2