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Popular >

distance (2,7),(-4,-3)

Solution

distance

(2, 7), (- 4, - 3)

Solution

234

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 7)

and

(- 4, - 3)

is

= (- 4 - 2)^{2} + (- 3 - 7)^{2}

Simplify

= 234

Popular Examples

extreme f(x)=4-2x^2 extreme points

f (x) = 4 - 2 x^{2}

y = 2

intercepts of f(x)=(-3x^2-x+3)/(x^2-1)intercepts

f (x) = \frac{- 3 x ^{2} - x + 3}{x ^{2} - 1}

domain of f(x)= 1/(sqrt(4-x^2))domain

f (x) = \frac{1}{4 - x ^{2}}

symmetry y=-x^2+10x-23 symmetry

y = - x^{2} + 10 x - 23

Frequently Asked Questions (FAQ)

What is the distance (2,7),(-4,-3) ?
The distance (2,7),(-4,-3) is 2sqrt(34)