What is the domain of f(x)=(sqrt(x-1))/(x^2+4) ?

The domain of f(x)=(sqrt(x-1))/(x^2+4) is x>= 1

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domain of f(x)=(sqrt(x-1))/(x^2+4)

domain

f (x) = \frac{x - 1}{x ^{2} + 4}

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

\frac{x}{7 x + 4}

x + 6 + 2

f (x) = \frac{2}{9 + 4 x}

f (x) = x^{2} ln (\frac{x}{2})

y = 2 x^{2} + 2 x - 4

What is the domain of f(x)=(sqrt(x-1))/(x^2+4) ?
The domain of f(x)=(sqrt(x-1))/(x^2+4) is x>= 1