What is the range of g(x)=sqrt(x) ?

The range of g(x)=sqrt(x) is f(x)>= 0

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range of g(x)=sqrt(x)

range

g (x) = x

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

\frac{8 x}{x + 5}

f (x) = - 2 x^{2} - 28 x - 96

f (x) = \frac{x + 6}{2 x ^{2} + 9 x - 18}

f (x) = \frac{11}{x}

f (x) = \frac{2 x ^{2} + 2 x - 12}{x ^{2} + x}