What is the asymptotes of f(x)=(x+6)/(2x^2+9x-18) ?

The asymptotes of f(x)=(x+6)/(2x^2+9x-18) is Vertical: x= 3/2 ,Horizontal: y=0

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asymptotes of f(x)=(x+6)/(2x^2+9x-18)

asymptotes

f (x) = \frac{x + 6}{2 x ^{2} + 9 x - 18}

Vertical : x = \frac{3}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 6}{2 x ^{2} + 9 x - 18} : x = \frac{3}{2}

Horizontal Asymptotes of

\frac{x + 6}{2 x ^{2} + 9 x - 18} : y = 0

Slant Asymptotes of

\frac{x + 6}{2 x ^{2} + 9 x - 18} :

None

Vertical : x = \frac{3}{2}, Horizontal : y = 0

f (x) = \frac{11}{x}

f (x) = \frac{2 x ^{2} + 2 x - 12}{x ^{2} + x}

f (x) = \frac{1}{2} + 1

f (x) = 17 x^{4} - 102 x^{2}

f (x) = - 8 x^{3} + 24 x + 9

What is the asymptotes of f(x)=(x+6)/(2x^2+9x-18) ?
The asymptotes of f(x)=(x+6)/(2x^2+9x-18) is Vertical: x= 3/2 ,Horizontal: y=0