What is the domain of f(x)= 1/(\sqrt[4]{x^2-5x)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-5x)} is x 5

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domain of f(x)= 1/(\sqrt[4]{x^2-5x)}

domain

x < 0 or x > 5

Interval Notation

(- \infty, 0) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

Find undefined (singularity) points:

x = 5, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 5

sec (x)

f (x) = lo g_{3} (x - 9)

f (x) = x - 3 = y

2 x^{3} - 3 x^{2} - 36 x

x = - 1

What is the domain of f(x)= 1/(\sqrt[4]{x^2-5x)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-5x)} is x<0\lor x>5