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Popular >

inverse of f(x)=log_{5}(2x-1)

Solution

inverse

f (x) = lo g_{5} (2 x - 1)

Solution

\frac{5 ^{x} + 1}{2}

Solution steps

y = lo g_{5} (2 x - 1)

Replace

x

with

y

x = lo g_{5} (2 y - 1)

Solve for

y, x = lo g_{5} (2 y - 1)

\frac{5 ^{x} + 1}{2}

Popular Examples

periodicity of f(x)=tan(x+pi/2)periodicity

f (x) = tan (x + \frac{π}{2})

domain of f(x)=(sqrt(9+x))/(2-x)domain

f (x) = \frac{9 + x}{2 - x}

periodicity of f(x)=5tan(x+pi/2)periodicity

f (x) = 5 tan (x + \frac{π}{2})

inflection x/(5+x^2)inflection points

\frac{x}{5 + x ^{2}}

critical f(x)=-x^4+6x^2 critical points

f (x) = - x^{4} + 6 x^{2}

Frequently Asked Questions (FAQ)

What is the inverse of f(x)=log_{5}(2x-1) ?
The inverse of f(x)=log_{5}(2x-1) is (5^x+1)/2