What is the asymptotes of f(x)=(-2x^2+5x+3)/(x+1) ?

The asymptotes of f(x)=(-2x^2+5x+3)/(x+1) is Vertical: x=-1,Slant: y=-2x+7

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asymptotes of f(x)=(-2x^2+5x+3)/(x+1)

asymptotes

f (x) = \frac{- 2 x ^{2} + 5 x + 3}{x + 1}

Vertical : x = - 1, Slant : y = - 2 x + 7

Solution steps

Vertical asymptotes of

\frac{- 2 x ^{2} + 5 x + 3}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{- 2 x ^{2} + 5 x + 3}{x + 1} :

None

Slant Asymptotes of

\frac{- 2 x ^{2} + 5 x + 3}{x + 1} : y = - 2 x + 7

Vertical : x = - 1, Slant : y = - 2 x + 7

f (x) = lo g_{5} (x - 1) + 4

f (x) = 5 - 2 x^{2}

\frac{1}{1 - x ^{n}}

f (x) = \frac{3}{5} x + \frac{1}{3}

f (x) = x^{10}

What is the asymptotes of f(x)=(-2x^2+5x+3)/(x+1) ?
The asymptotes of f(x)=(-2x^2+5x+3)/(x+1) is Vertical: x=-1,Slant: y=-2x+7