What is the domain of f(x)=sqrt(x^2-4x+5) ?

The domain of f(x)=sqrt(x^2-4x+5) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2-4x+5)

domain

f (x) = x^{2} - 4 x + 5

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - (x - 5)^{2} - 9

f (t) = \frac{1}{( 7 t ^{5} - t ^{4} + 2 ) ^{10}}

f (x) = 2 x^{2} - 1

f (x) = 4 x^{4} + 16 x^{3}

f (x) = \frac{35}{x ^{2} + 7 x}

What is the domain of f(x)=sqrt(x^2-4x+5) ?
The domain of f(x)=sqrt(x^2-4x+5) is -infinity <x<infinity