What is the critical f(θ)=6cos(θ)+3sin^2(θ) ?

The critical f(θ)=6cos(θ)+3sin^2(θ) is θ=2pin,θ=pi+2pin

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critical f(θ)=6cos(θ)+3sin^2(θ)

critical points

f (θ) = 6 cos (θ) + 3 sin^{2} (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

6 cos (θ) + 3 sin^{2} (θ)

Find where

f^{'} (θ)

is equal to zero or undefined

θ = 2 πn, θ = π + 2 πn

Identify critical points not in

f (θ)

domain

Domain of

6 cos (θ) + 3 sin^{2} (θ) : - \infty < θ < \infty

All critical points are in domain

θ = 2 πn, θ = π + 2 πn

f (x) = lo g_{10} (x + 3)

f (x) = x^{2} + 36

2 x^{2} + 4 x - 10

f (x) = \frac{2 + x}{5 - x}

y = - 3 sin (x)

What is the critical f(θ)=6cos(θ)+3sin^2(θ) ?
The critical f(θ)=6cos(θ)+3sin^2(θ) is θ=2pin,θ=pi+2pin