What is the range of f(x)=-sqrt(49-x^2) ?

The range of f(x)=-sqrt(49-x^2) is -7<= f(x)<= 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=-sqrt(49-x^2)

range

f (x) = - 49 - x^{2}

- 7 \leq f (x) \leq 0

Interval Notation

[- 7, 0]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

- 49 - x^{2} : - 7 \leq x \leq 7

Extreme Points of

- 49 - x^{2} :

Maximum

(- 7, 0),

Minimum

(0, - 7),

Maximum

(7, 0)

Find the range for the interval

- 7 \leq x \leq 7 : - 7 \leq f (x) \leq 0

Combine the ranges of all domain intervals to obtain the function range

- 7 \leq f (x) \leq 0

(3, - 6), (7, 10)

f (x) = (7 - x)^{\frac{1}{4}}

2 x^{2} - x + 4

x + 7 - x

What is the range of f(x)=-sqrt(49-x^2) ?
The range of f(x)=-sqrt(49-x^2) is -7<= f(x)<= 0