What is the midpoint (-1/3 , 2/3),(-11/3 ,-8/3) ?

The midpoint (-1/3 , 2/3),(-11/3 ,-8/3) is (-2,-1)

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midpoint (-1/3 , 2/3),(-11/3 ,-8/3)

midpoint

(- \frac{1}{3}, \frac{2}{3}), (- \frac{11}{3}, - \frac{8}{3})

(- 2, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{1}{3}, \frac{2}{3}), (x_{2}, y_{2}) = (- \frac{11}{3}, - \frac{8}{3})

= (\frac{- \frac{11}{3} - \frac{1}{3}}{2}, \frac{- \frac{8}{3} + \frac{2}{3}}{2})

Refine

= (- 2, - 1)

(3, 5), (- 1, 5)

f (x) = \frac{2 x + 5}{x + 2}

f (x) = \frac{1}{arccos ( t - 2 )}

y = 9 x^{2}

f (x) = lo g_{5} (x + 2)

What is the midpoint (-1/3 , 2/3),(-11/3 ,-8/3) ?
The midpoint (-1/3 , 2/3),(-11/3 ,-8/3) is (-2,-1)