What is the slope ofintercept-5x+4y=0 ?

The slope ofintercept-5x+4y=0 is y= 5/4 x+0

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slope ofintercept-5x+4y=0

slope intercept

- 5 x + 4 y = 0

y = \frac{5}{4} x + 0

Solution steps

- 5 x + 4 y = 0

Convert to slope intercept form:

y = \frac{5}{4} x

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = \frac{5}{4} x + 0

f (x) = \frac{10 x + 40}{x - 5}

f (x) = sin (\frac{x}{2})

y = - \frac{3}{4} x + 2

y = sin (x)

f (x) = \frac{1}{x ^{2} + 2}

What is the slope ofintercept-5x+4y=0 ?
The slope ofintercept-5x+4y=0 is y= 5/4 x+0