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Popular >

midpoint (-5,0),(-9,-6)

Solution

midpoint

(- 5, 0), (- 9, - 6)

Solution

(- 7, - 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 5, 0), (x_{2}, y_{2}) = (- 9, - 6)

= (\frac{- 9 - 5}{2}, \frac{- 6 + 0}{2})

Refine

= (- 7, - 3)

Graph

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f (x) = \frac{1}{4} x^{2} - 5

inverse of 8 inverse

8

range of (x^2)/(x^2+4)range

\frac{x ^{2}}{x ^{2} + 4}

inverse of f(x)=(x+17)/(x-16)inverse

f (x) = \frac{x + 17}{x - 16}

domain of h(x)=(x+1)^3+3 domain

h (x) = (x + 1)^{3} + 3

Frequently Asked Questions (FAQ)

What is the midpoint (-5,0),(-9,-6) ?
The midpoint (-5,0),(-9,-6) is (-7,-3)