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Popular >

distance (1,-1),(2,-6)

Solution

distance

(1, - 1), (2, - 6)

Solution

26

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, - 1)

and

(2, - 6)

is

= (2 - 1)^{2} + (- 6 - (- 1))^{2}

Simplify

= 26

Popular Examples

vertices y=x^2-2x-24 vertices

y = x^{2} - 2 x - 24

range of f(x)=sqrt(x^2-6x+8)range

f (x) = x^{2} - 6 x + 8

domain of \sqrt[5]{x/5}domain

extreme f(x)=(x/(1+x^2))extreme points

f (x) = (\frac{x}{1 + x ^{2}})

domain of f(x)=ln(7-x)domain

f (x) = ln (7 - x)

Frequently Asked Questions (FAQ)

What is the distance (1,-1),(2,-6) ?
The distance (1,-1),(2,-6) is square root of 26