What is the domain of f(x)=arctan((x-1)/(x+1)) ?

The domain of f(x)=arctan((x-1)/(x+1)) is x -1

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domain of f(x)=arctan((x-1)/(x+1))

domain

f (x) = arctan (\frac{x - 1}{x + 1})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = x^{3} - 4 x

f (x) = \frac{- 7 x + 9}{- 4 x - 3}

f (x) = \frac{x ^{2} - 9}{x - 5}

y + 3 = \frac{1}{2} (x + 10)

lo g_{\frac{1}{3}} (x)

What is the domain of f(x)=arctan((x-1)/(x+1)) ?
The domain of f(x)=arctan((x-1)/(x+1)) is x<-1\lor x>-1