What is the domain of f(x)=sqrt(-x^2-2x+3) ?

The domain of f(x)=sqrt(-x^2-2x+3) is -3<= x<= 1

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domain of f(x)=sqrt(-x^2-2x+3)

domain

f (x) = - x^{2} - 2 x + 3

- 3 \leq x \leq 1

Interval Notation

[- 3, 1]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 1

The function domain

- 3 \leq x \leq 1

f (x) = 3 x (4 - x)^{3}

f (x) = \frac{( 4 x + 3 )}{7}

- 2 sin (3 x + \frac{π}{2})

(2.25, 2.25), (- 1.5, 5.79)

f (x) = \frac{7}{x ^{2} - 16}

What is the domain of f(x)=sqrt(-x^2-2x+3) ?
The domain of f(x)=sqrt(-x^2-2x+3) is -3<= x<= 1