What is the line m=(-1)/4 ,(12,-3) ?

The line m=(-1)/4 ,(12,-3) is y=(-1)/4 x

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line m=(-1)/4 ,(12,-3)

line

m = \frac{- 1}{4}, (12, - 3)

y = \frac{- 1}{4} x

Solution steps

Compute the line equation

y = mx + b

for slope m=

\frac{- 1}{4}

and passing through

(12, - 3)

Compute the

y

intercept:

b = 0

Construct the line equation

y = mx + b

where

m = \frac{- 1}{4}

and

b = 0

y = \frac{- 1}{4} x

f (x) = \frac{1}{7} x + 6

y = \frac{1}{3 x - x ^{2}}

\frac{16 - x ^{2}}{x + 1}

f (x) = x^{3} - 8

f (x) = \frac{x}{x ^{3} - 1}