What is the domain of (x^2+x)/(-4x^2-8x+12) ?

The domain of (x^2+x)/(-4x^2-8x+12) is x 1

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domain of (x^2+x)/(-4x^2-8x+12)

domain

\frac{x ^{2} + x}{- 4 x ^{2} - 8 x + 12}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = 1

The function domain

x < - 3 or - 3 < x < 1 or x > 1

f (x) = tan (x)

3 x - 6

(- 11, 0), (9, - 1)

f (x) = \frac{ln ( x ^{2} + 1 )}{x ^{2} + 1}

x^{2} + \frac{16}{x}

What is the domain of (x^2+x)/(-4x^2-8x+12) ?
The domain of (x^2+x)/(-4x^2-8x+12) is x<-3\lor-3<x<1\lor x>1