What is the range of f(x)=t^2-5 ?

The range of f(x)=t^2-5 is f(x)>=-5

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range of f(x)=t^2-5

range

f (x) = t^{2} - 5

f (x) \geq - 5

Interval Notation

[- 5, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

t^{2} - 5

Inverse of

t^{2} - 5 : t + 5, - t + 5

t + 5, - t + 5

Find the domain of each inverse function

Domain of

t + 5 : t \geq - 5

Domain of

- t + 5 : t \geq - 5

Combine the intervals

f (x) \geq - 5

\frac{ln ( x - 1 )}{x - 1}

(2, 3), (3, 7)

f (x) = \frac{3}{2} (2 x + 1)

- 4 cos (2 π x) + 2

f (x) = \frac{4 x + 4}{x ^{2} + 4 x + 3}