What is the domain of f(x)=sqrt((x+3)/(2x-1)) ?

The domain of f(x)=sqrt((x+3)/(2x-1)) is x 1/2

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domain of f(x)=sqrt((x+3)/(2x-1))

domain

f (x) = \frac{x + 3}{2 x - 1}

x \leq - 3 or x > \frac{1}{2}

Interval Notation

(- \infty, - 3] \cup (\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x > \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x \leq - 3 or x > \frac{1}{2}

f (x) = x^{2} + 7 x + 5

\frac{2 x ^{2} - 5 x - 12}{x ^{2} - 16}

f (x) = 2 x + 3 y = - 24

y = - \frac{1}{3} x + 3

What is the domain of f(x)=sqrt((x+3)/(2x-1)) ?
The domain of f(x)=sqrt((x+3)/(2x-1)) is x<=-3\lor x> 1/2