What is the domain of f(x)=ln(sqrt(x)-1) ?

The domain of f(x)=ln(sqrt(x)-1) is x>1

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domain of f(x)=ln(sqrt(x)-1)

domain

f (x) = ln (x - 1)

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

f (x) = x^{2} + 5

\frac{e ^{x} + 1}{e ^{x} - 2}

f (x) = \frac{2 x ^{2}}{x ^{2} - 9}

y = 2 x + 1

f (x) = 2 x^{2} - 5 x

What is the domain of f(x)=ln(sqrt(x)-1) ?
The domain of f(x)=ln(sqrt(x)-1) is x>1