What is the asymptotes of f(x)= 1/(x^2-16) ?

The asymptotes of f(x)= 1/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=0

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asymptotes of f(x)= 1/(x^2-16)

asymptotes

f (x) = \frac{1}{x ^{2} - 16}

Vertical : x = - 4, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 16} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{1}{x ^{2} - 16} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 16} :

None

Vertical : x = - 4, x = 4, Horizontal : y = 0

f (x) = lo g_{3} (x - 2)

f (x) = \frac{12 x}{x ^{2} + 4}

f (x) = x^{3} \cdot e^{(- x)}

f (x) = cot (\frac{x}{2} - \frac{π}{4}) + 1

x^{\frac{1}{7}} (x + 8)

What is the asymptotes of f(x)= 1/(x^2-16) ?
The asymptotes of f(x)= 1/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=0