What is the critical f(x)=(12x)/(x^2+4) ?

The critical f(x)=(12x)/(x^2+4) is x=-2,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=(12x)/(x^2+4)

critical points

f (x) = \frac{12 x}{x ^{2} + 4}

x = - 2, x = 2

Solution steps

\frac{12 x}{x ^{2} + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{12 x}{x ^{2} + 4} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 2

f (x) = x^{3} \cdot e^{(- x)}

f (x) = cot (\frac{x}{2} - \frac{π}{4}) + 1

x^{\frac{1}{7}} (x + 8)

f (x) = \frac{( x ^{2} - 3 x + 2 )}{( x ^{2} + 2 x - 3 )}

f (x) = x^{4} - 81

What is the critical f(x)=(12x)/(x^2+4) ?
The critical f(x)=(12x)/(x^2+4) is x=-2,x=2