What is the inverse of f(x)=-3x^2+3 ?

The inverse of f(x)=-3x^2+3 is sqrt(-(x-3)/3),-sqrt(-(x-3)/3)

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inverse of f(x)=-3x^2+3

inverse

f (x) = - 3 x^{2} + 3

- \frac{x - 3}{3}, - - \frac{x - 3}{3}

Solution steps

y = - 3 x^{2} + 3

Replace

x

with

y

x = - 3 y^{2} + 3

Solve for

y, x = - 3 y^{2} + 3

- \frac{x - 3}{3}, - - \frac{x - 3}{3}

f (x) = \frac{8 x}{x ^{2} - 9}

f (x) = 3 \cdot 0. 2^{x}

(x^{2} + 3)^{2}

f (x) = 25 - x^{2} + x - 9

f (x) = 3 x^{3} + 9

What is the inverse of f(x)=-3x^2+3 ?
The inverse of f(x)=-3x^2+3 is sqrt(-(x-3)/3),-sqrt(-(x-3)/3)