What is the inverse of f(x)=x^2-10x,x>= 5 ?

The inverse of f(x)=x^2-10x,x>= 5 is 5+sqrt(x+25),5-sqrt(x+25)

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inverse of f(x)=x^2-10x,x>= 5

inverse

f (x) = x^{2} - 10 x, x \geq 5

5 + x + 25, 5 - x + 25

Solution steps

y = x^{2} - 10 x

Replace

x

with

y

x = y^{2} - 10 y

Solve for

y, x = y^{2} - 10 y

5 + x + 25, 5 - x + 25

f (x) = ln (x (x - 2))

y = - 6 x + 3, (- 6, 7)

\frac{1}{1 + x}

f (x) = x^{2} - 4 x + 7

f (x) = \frac{1}{x ^{2} - 3 x + 2}

What is the inverse of f(x)=x^2-10x,x>= 5 ?
The inverse of f(x)=x^2-10x,x>= 5 is 5+sqrt(x+25),5-sqrt(x+25)