What is the critical f(x)=5+1/x+1/(x^2) ?

The critical f(x)=5+1/x+1/(x^2) is x=-2

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critical f(x)=5+1/x+1/(x^2)

critical points

f (x) = 5 + \frac{1}{x} + \frac{1}{x ^{2}}

x = - 2

Solution steps

5 + \frac{1}{x} + \frac{1}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

5 + \frac{1}{x} + \frac{1}{x ^{2}} : x < 0 or x > 0

5 + \frac{1}{x} + \frac{1}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - 2

f (x) = \frac{1}{4 x - 3}

csc (x)

f (x) = 16 - x^{2}

13, - 11

f (x) = 3 x^{2} - 2

What is the critical f(x)=5+1/x+1/(x^2) ?
The critical f(x)=5+1/x+1/(x^2) is x=-2