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Popular >

distance (5,-5),(-1,-1)

Solution

distance

(5, - 5), (- 1, - 1)

Solution

213

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 5)

and

(- 1, - 1)

is

= (- 1 - 5)^{2} + (- 1 - (- 5))^{2}

Simplify

= 213

Popular Examples

parity f(x)= x/(x^2-3)parity

f (x) = \frac{x}{x ^{2} - 3}

domain of f(x)=(x-5)/(2x+3)domain

f (x) = \frac{x - 5}{2 x + 3}

asymptotes of f(x)=(-6)/(x+6)asymptotes

f (x) = \frac{- 6}{x + 6}

critical 2(x-6)^{2/3}critical points

2 (x - 6)^{\frac{2}{3}}

inverse of f(x)=18500(0.04-x^2)inverse

f (x) = 18500 (0.04 - x^{2})

Frequently Asked Questions (FAQ)

What is the distance (5,-5),(-1,-1) ?
The distance (5,-5),(-1,-1) is 2sqrt(13)