What is the range of f(x)= x/(sqrt(4-x^2)) ?

The range of f(x)= x/(sqrt(4-x^2)) is -infinity <f(x)<infinity

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range of f(x)= x/(sqrt(4-x^2))

range

f (x) = \frac{x}{4 - x ^{2}}

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x}{4 - x ^{2}} : - 2 < x < 2

Extreme Points of

\frac{x}{4 - x ^{2}} :

None

Find the range for the interval

- 2 < x < 2 : - \infty < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

- \infty < f (x) < \infty

f (x) = (- x^{2} + 6 x - 8)^{(\frac{1}{2})}

f (x) = x - 3 + 4

f (x) = \frac{1}{x + 2} + 9

f (x) = \frac{x - 1}{2 + x}

\frac{2}{( 2 x - 5 )}

What is the range of f(x)= x/(sqrt(4-x^2)) ?
The range of f(x)= x/(sqrt(4-x^2)) is -infinity <f(x)<infinity