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Popular >

extreme f(x)=-t^2+8t+2

Solution

extreme points

f (x) = - t^{2} + 8 t + 2

Solution

Maximum (4, 18)

Solution steps

f^{'} (t) = - 2 t + 8

Find intervals:

Increasing

: - \infty < t < 4,

Decreasing

: 4 < t < \infty

Plug

t = 4

into

- t^{2} + 8 t + 2 : 18

Maximum (4, 18)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-t^2+8t+2 ?
The extreme f(x)=-t^2+8t+2 is Maximum(4,18)