What is the perpendicular y=-7x+8 ?

The perpendicular y=-7x+8 is y= 1/7 x+b

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perpendicular y=-7x+8

perpendicular

y = - 7 x + 8

y = \frac{1}{7} x + b

Solution steps

Find the slope of

y = - 7 x + 8 : m = - 7

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{7}

Line with slope m=

\frac{1}{7} : y = \frac{1}{7} x + b

y = \frac{1}{7} x + b

f (x) = - \frac{1}{4} x - 2

f (x) = x^{2} + 2 x - 8

f (x) = x^{2} - 6 x - 7

3 x + 5 y = 45, (- 5, 6)

2 (x - 3) - 4 (y + 2) = 8