What is the inverse of f(x)= x/(sqrt(4-x^2)) ?

The inverse of f(x)= x/(sqrt(4-x^2)) is (2xsqrt(x^2+1))/(x^2+1),-(2xsqrt(x^2+1))/(x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= x/(sqrt(4-x^2))

inverse

f (x) = \frac{x}{4 - x ^{2}}

\frac{2 x x ^{2} + 1}{x ^{2} + 1}, - \frac{2 x x ^{2} + 1}{x ^{2} + 1}

Solution steps

y = \frac{x}{4 - x ^{2}}

Replace

x

with

y

x = \frac{y}{4 - y ^{2}}

Solve for

y, x = \frac{y}{4 - y ^{2}}

\frac{2 x x ^{2} + 1}{x ^{2} + 1}, - \frac{2 x x ^{2} + 1}{x ^{2} + 1}

y = x - 6

f (x) = lo g_{2} (x - 2)

(- 10 - 5) m = \frac{1}{5}

f (x) = x + 6

f (x) = \frac{x + 7}{x - 3}

What is the inverse of f(x)= x/(sqrt(4-x^2)) ?
The inverse of f(x)= x/(sqrt(4-x^2)) is (2xsqrt(x^2+1))/(x^2+1),-(2xsqrt(x^2+1))/(x^2+1)