What is the extreme f(x)=x^3-12x+3 ?

The extreme f(x)=x^3-12x+3 is Maximum(-2,19),Minimum(2,-13)

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extreme f(x)=x^3-12x+3

extreme points

f (x) = x^{3} - 12 x + 3

Maximum (- 2, 19), Minimum (2, - 13)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 3 : 19

Maximum (- 2, 19)

Plug

x = 2

into

x^{3} - 12 x + 3 : - 13

Minimum (2, - 13)

Maximum (- 2, 19), Minimum (2, - 13)

\frac{3}{2} sin (2 π x)

f (x) = t^{2} - 10 t + 25

f (x) = \frac{1}{x ^{2} + 1}

f (x) = \frac{2 x}{3 x ^{2} + 1}

What is the extreme f(x)=x^3-12x+3 ?
The extreme f(x)=x^3-12x+3 is Maximum(-2,19),Minimum(2,-13)