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Popular >

extreme f(x)=t^2-10t+25

Solution

extreme points

f (x) = t^{2} - 10 t + 25

Solution

Minimum (5, 0)

Solution steps

f^{'} (t) = 2 t - 10

Find intervals:

Decreasing

: - \infty < t < 5,

Increasing

: 5 < t < \infty

Plug

t = 5

into

t^{2} - 10 t + 25 : 0

Minimum (5, 0)

Popular Examples

f(x)= 1/(x^2+1)

f (x) = \frac{1}{x ^{2} + 1}

parity f(x)= 1/(\sqrt[3]{x)}parity

asymptotes of f(x)=(2x)/(3x^2+1)asymptotes

f (x) = \frac{2 x}{3 x ^{2} + 1}

critical f(x,y)=4x^3 critical points

f (x, y) = 4 x^{3}

periodicity of f(x)=-2sin(-3x+pi/2)periodicity

f (x) = - 2 sin (- 3 x + \frac{π}{2})

Frequently Asked Questions (FAQ)

What is the extreme f(x)=t^2-10t+25 ?
The extreme f(x)=t^2-10t+25 is Minimum(5,0)