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Popular >

distance (-2,1),(2,7)

Solution

distance

(- 2, 1), (2, 7)

Solution

213

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 1)

and

(2, 7)

is

= (2 - (- 2))^{2} + (7 - 1)^{2}

Simplify

= 213

Popular Examples

range of f(x)=(x^2+6x-7)/(x^2+2x-3)range

f (x) = \frac{x ^{2} + 6 x - 7}{x ^{2} + 2 x - 3}

inflection y=-1/3 x^3+2x^2-1 inflection points

y = - \frac{1}{3} x^{3} + 2 x^{2} - 1

critical y=(x-2)^3 critical points

y = (x - 2)^{3}

inverse of f(x)=x^2-36 inverse

f (x) = x^{2} - 36

domain of f(x)=e^{-x}+2 domain

f (x) = e^{- x} + 2

Frequently Asked Questions (FAQ)

What is the distance (-2,1),(2,7) ?
The distance (-2,1),(2,7) is 2sqrt(13)